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4113102040403 = 37889108556627
BaseRepresentation
bin111011110110100111111…
…111000110110101010011
3112120012122011010122202112
4323312213333012311103
51014342113110243103
612425311043135535
7603106334330126
oct73664777066523
915505564118675
104113102040403
1113463a1967634
125651916745ab
1323ab2cb862b5
1410310a4cc3bd
1571ed05a0cd8
hex3bda7fc6d53

4113102040403 has 4 divisors (see below), whose sum is σ = 4113210634920. Its totient is φ = 4112993445888.

The previous prime is 4113102040381. The next prime is 4113102040423. The reversal of 4113102040403 is 3040402013114.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4113102040403 - 214 = 4113102024019 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4113102040423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54240425 + ... + 54316202.

It is an arithmetic number, because the mean of its divisors is an integer number (1028302658730).

Almost surely, 24113102040403 is an apocalyptic number.

4113102040403 is a deficient number, since it is larger than the sum of its proper divisors (108594517).

4113102040403 is a wasteful number, since it uses less digits than its factorization.

4113102040403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 108594516.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 4113102040403 its reverse (3040402013114), we get a palindrome (7153504053517).

The spelling of 4113102040403 in words is "four trillion, one hundred thirteen billion, one hundred two million, forty thousand, four hundred three".

Divisors: 1 37889 108556627 4113102040403