Base | Representation |
---|---|
bin | 111011110110100111111… |
… | …111000110110101010011 |
3 | 112120012122011010122202112 |
4 | 323312213333012311103 |
5 | 1014342113110243103 |
6 | 12425311043135535 |
7 | 603106334330126 |
oct | 73664777066523 |
9 | 15505564118675 |
10 | 4113102040403 |
11 | 13463a1967634 |
12 | 5651916745ab |
13 | 23ab2cb862b5 |
14 | 10310a4cc3bd |
15 | 71ed05a0cd8 |
hex | 3bda7fc6d53 |
4113102040403 has 4 divisors (see below), whose sum is σ = 4113210634920. Its totient is φ = 4112993445888.
The previous prime is 4113102040381. The next prime is 4113102040423. The reversal of 4113102040403 is 3040402013114.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4113102040403 - 214 = 4113102024019 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4113102040423) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54240425 + ... + 54316202.
It is an arithmetic number, because the mean of its divisors is an integer number (1028302658730).
Almost surely, 24113102040403 is an apocalyptic number.
4113102040403 is a deficient number, since it is larger than the sum of its proper divisors (108594517).
4113102040403 is a wasteful number, since it uses less digits than its factorization.
4113102040403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 108594516.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 4113102040403 its reverse (3040402013114), we get a palindrome (7153504053517).
The spelling of 4113102040403 in words is "four trillion, one hundred thirteen billion, one hundred two million, forty thousand, four hundred three".
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