Base | Representation |
---|---|
bin | 111011110110101000100… |
… | …010000101111111000001 |
3 | 112120012122210101121210011 |
4 | 323312220202011333001 |
5 | 1014342122432240334 |
6 | 12425312011504521 |
7 | 603106505306314 |
oct | 73665042057701 |
9 | 15505583347704 |
10 | 4113111211969 |
11 | 13463a7061341 |
12 | 565194758141 |
13 | 23ab31a47a66 |
14 | 10310b7d897b |
15 | 71ed12b3564 |
hex | 3bda8885fc1 |
4113111211969 has 2 divisors, whose sum is σ = 4113111211970. Its totient is φ = 4113111211968.
The previous prime is 4113111211943. The next prime is 4113111212033. The reversal of 4113111211969 is 9691121113114.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4108473601969 + 4637610000 = 2026937^2 + 68100^2 .
It is a cyclic number.
It is not a de Polignac number, because 4113111211969 - 213 = 4113111203777 is a prime.
It is a super-2 number, since 2×41131112119692 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4113111218969) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056555605984 + 2056555605985.
It is an arithmetic number, because the mean of its divisors is an integer number (2056555605985).
Almost surely, 24113111211969 is an apocalyptic number.
It is an amenable number.
4113111211969 is a deficient number, since it is larger than the sum of its proper divisors (1).
4113111211969 is an equidigital number, since it uses as much as digits as its factorization.
4113111211969 is an evil number, because the sum of its binary digits is even.
The product of its digits is 11664, while the sum is 40.
The spelling of 4113111211969 in words is "four trillion, one hundred thirteen billion, one hundred eleven million, two hundred eleven thousand, nine hundred sixty-nine".
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