Search a number
-
+
4113111212033 is a prime number
BaseRepresentation
bin111011110110101000100…
…010000110000000000001
3112120012122210101121212112
4323312220202012000001
51014342122432241113
612425312011505105
7603106505306435
oct73665042060001
915505583347775
104113111212033
1113463a706139a
12565194758195
1323ab31a47ab5
1410310b7d89c5
1571ed12b35a8
hex3bda8886001

4113111212033 has 2 divisors, whose sum is σ = 4113111212034. Its totient is φ = 4113111212032.

The previous prime is 4113111211969. The next prime is 4113111212047. The reversal of 4113111212033 is 3302121113114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2771748830449 + 1341362381584 = 1664857^2 + 1158172^2 .

It is a cyclic number.

It is not a de Polignac number, because 4113111212033 - 26 = 4113111211969 is a prime.

It is not a weakly prime, because it can be changed into another prime (4113111212053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056555606016 + 2056555606017.

It is an arithmetic number, because the mean of its divisors is an integer number (2056555606017).

Almost surely, 24113111212033 is an apocalyptic number.

It is an amenable number.

4113111212033 is a deficient number, since it is larger than the sum of its proper divisors (1).

4113111212033 is an equidigital number, since it uses as much as digits as its factorization.

4113111212033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 4113111212033 its reverse (3302121113114), we get a palindrome (7415232325147).

The spelling of 4113111212033 in words is "four trillion, one hundred thirteen billion, one hundred eleven million, two hundred twelve thousand, thirty-three".