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41131200340121 is a prime number
BaseRepresentation
bin10010101101000100110101…
…00101011110000010011001
312101122002211001221021111212
421112202122211132002121
520342343144241340441
6223251225041232505
711443426326223013
oct1126423245360231
9171562731837455
1041131200340121
111211870a338421
124743603932735
1319c486a31b048
14a22a915a91b3
154b4db489ceeb
hex25689a95e099

41131200340121 has 2 divisors, whose sum is σ = 41131200340122. Its totient is φ = 41131200340120.

The previous prime is 41131200340067. The next prime is 41131200340163. The reversal of 41131200340121 is 12104300213114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 40322639700121 + 808560640000 = 6350011^2 + 899200^2 .

It is a cyclic number.

It is not a de Polignac number, because 41131200340121 - 234 = 41114020470937 is a prime.

It is not a weakly prime, because it can be changed into another prime (41131200340621) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20565600170060 + 20565600170061.

It is an arithmetic number, because the mean of its divisors is an integer number (20565600170061).

Almost surely, 241131200340121 is an apocalyptic number.

It is an amenable number.

41131200340121 is a deficient number, since it is larger than the sum of its proper divisors (1).

41131200340121 is an equidigital number, since it uses as much as digits as its factorization.

41131200340121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 41131200340121 its reverse (12104300213114), we get a palindrome (53235500553235).

The spelling of 41131200340121 in words is "forty-one trillion, one hundred thirty-one billion, two hundred million, three hundred forty thousand, one hundred twenty-one".