411312101213149 has 2 divisors, whose sum is σ = 411312101213150. Its totient is φ = 411312101213148.

The previous prime is 411312101213089. The next prime is 411312101213161. The reversal of 411312101213149 is 941312101213114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 218348941923225 + 192963159289924 = 14776635^2 + 13891118^2 .

It is a cyclic number.

It is not a de Polignac number, because 411312101213149 - 2¹¹ = 411312101211101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (411312101213179) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205656050606574 + 205656050606575.

It is an arithmetic number, because the mean of its divisors is an integer number (205656050606575).

Almost surely, 2^{411312101213149} is an apocalyptic number.

It is an amenable number.

411312101213149 is a deficient number, since it is larger than the sum of its proper divisors (1).

411312101213149 is an equidigital number, since it uses as much as digits as its factorization.

411312101213149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 34.

The spelling of 411312101213149 in words is "four hundred eleven trillion, three hundred twelve billion, one hundred one million, two hundred thirteen thousand, one hundred forty-nine".