41131214143 has 4 divisors (see below), whose sum is σ = 41159918448. Its totient is φ = 41102509840.

The previous prime is 41131214099. The next prime is 41131214147. The reversal of 41131214143 is 34141213114.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 41131214143 - 2²⁵ = 41097659711 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (41131214147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14350003 + ... + 14352868.

It is an arithmetic number, because the mean of its divisors is an integer number (10289979612).

Almost surely, 2^41131214143 is an apocalyptic number.

41131214143 is a deficient number, since it is larger than the sum of its proper divisors (28704305).

41131214143 is a wasteful number, since it uses less digits than its factorization.

41131214143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28704304.

The product of its digits is 1152, while the sum is 25.

Adding to 41131214143 its reverse (34141213114), we get a palindrome (75272427257).

The spelling of 41131214143 in words is "forty-one billion, one hundred thirty-one million, two hundred fourteen thousand, one hundred forty-three".