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41131326149 is a prime number
BaseRepresentation
bin100110010011100111…
…100011101011000101
310221011111211212012222
4212103213203223011
51133214104414044
630521231022125
72654162334524
oct462347435305
9127144755188
1041131326149
111649761a131
127b7a96a945
133b56580a14
141dc29424bb
15110aea98ee
hex9939e3ac5

41131326149 has 2 divisors, whose sum is σ = 41131326150. Its totient is φ = 41131326148.

The previous prime is 41131326113. The next prime is 41131326169. The reversal of 41131326149 is 94162313114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 32619972100 + 8511354049 = 180610^2 + 92257^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41131326149 is a prime.

It is a super-2 number, since 2×411313261492 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41131326169) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20565663074 + 20565663075.

It is an arithmetic number, because the mean of its divisors is an integer number (20565663075).

Almost surely, 241131326149 is an apocalyptic number.

It is an amenable number.

41131326149 is a deficient number, since it is larger than the sum of its proper divisors (1).

41131326149 is an equidigital number, since it uses as much as digits as its factorization.

41131326149 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 15552, while the sum is 35.

The spelling of 41131326149 in words is "forty-one billion, one hundred thirty-one million, three hundred twenty-six thousand, one hundred forty-nine".