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4113134132342 = 22056567066171
BaseRepresentation
bin111011110110101001111…
…001100001110001110110
3112120012201101112002121212
4323312221321201301312
51014342144314213332
612425314151041422
7603110204160464
oct73665171416166
915505641462555
104113134132342
111346408a967a4
125651a0370272
1323ab36711501
14103110883834
1571ed32de8b2
hex3bda9e61c76

4113134132342 has 4 divisors (see below), whose sum is σ = 6169701198516. Its totient is φ = 2056567066170.

The previous prime is 4113134132309. The next prime is 4113134132449. The reversal of 4113134132342 is 2432314313114.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 4113134132299 and 4113134132308.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1028283533084 + ... + 1028283533087.

It is an arithmetic number, because the mean of its divisors is an integer number (1542425299629).

Almost surely, 24113134132342 is an apocalyptic number.

4113134132342 is a deficient number, since it is larger than the sum of its proper divisors (2056567066174).

4113134132342 is a wasteful number, since it uses less digits than its factorization.

4113134132342 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2056567066173.

The product of its digits is 20736, while the sum is 32.

Adding to 4113134132342 its reverse (2432314313114), we get a palindrome (6545448445456).

The spelling of 4113134132342 in words is "four trillion, one hundred thirteen billion, one hundred thirty-four million, one hundred thirty-two thousand, three hundred forty-two".

Divisors: 1 2 2056567066171 4113134132342