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411314320240111 is a prime number
BaseRepresentation
bin101110110000101101001001…
…1111100101110110111101111
31222221100021011011220101121201
41131201122103330232313233
5412402433211440140421
64014443105024110331
7152431323202105441
oct13541322374566757
91887307134811551
10411314320240111
1110a06a472919192
123a16b5797653a7
1314867a0a545b62
14737da0db5a491
153284369285b91
hex1761693f2edef

411314320240111 has 2 divisors, whose sum is σ = 411314320240112. Its totient is φ = 411314320240110.

The previous prime is 411314320240067. The next prime is 411314320240127. The reversal of 411314320240111 is 111042023413114.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 411314320240111 - 229 = 411313783369199 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 411314320240111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (411314320540111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205657160120055 + 205657160120056.

It is an arithmetic number, because the mean of its divisors is an integer number (205657160120056).

Almost surely, 2411314320240111 is an apocalyptic number.

411314320240111 is a deficient number, since it is larger than the sum of its proper divisors (1).

411314320240111 is an equidigital number, since it uses as much as digits as its factorization.

411314320240111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 411314320240111 its reverse (111042023413114), we get a palindrome (522356343653225).

The spelling of 411314320240111 in words is "four hundred eleven trillion, three hundred fourteen billion, three hundred twenty million, two hundred forty thousand, one hundred eleven".