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4113145501 is a prime number
BaseRepresentation
bin1111010100101001…
…1001111010011101
3101121122121102220021
43311022121322131
531410431124001
61520050552141
7203633105563
oct36512317235
911548542807
104113145501
111820844103
12969598651
135071b870a
142b03a7a33
15191174ba1
hexf5299e9d

4113145501 has 2 divisors, whose sum is σ = 4113145502. Its totient is φ = 4113145500.

The previous prime is 4113145493. The next prime is 4113145523. The reversal of 4113145501 is 1055413114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4112656900 + 488601 = 64130^2 + 699^2 .

It is a cyclic number.

It is not a de Polignac number, because 4113145501 - 23 = 4113145493 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4113145301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056572750 + 2056572751.

It is an arithmetic number, because the mean of its divisors is an integer number (2056572751).

Almost surely, 24113145501 is an apocalyptic number.

It is an amenable number.

4113145501 is a deficient number, since it is larger than the sum of its proper divisors (1).

4113145501 is an equidigital number, since it uses as much as digits as its factorization.

4113145501 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1200, while the sum is 25.

The square root of 4113145501 is about 64133.8093442141. The cubic root of 4113145501 is about 1602.2293793340.

Adding to 4113145501 its reverse (1055413114), we get a palindrome (5168558615).

The spelling of 4113145501 in words is "four billion, one hundred thirteen million, one hundred forty-five thousand, five hundred one".