Base | Representation |
---|---|
bin | 100110010011101000… |
… | …001110100110101001 |
3 | 10221011112011210102201 |
4 | 212103220032212221 |
5 | 1133214131030433 |
6 | 30521234500201 |
7 | 2654163666301 |
oct | 462350164651 |
9 | 127145153381 |
10 | 41131501993 |
11 | 1649772a25a |
12 | 7b7aa34661 |
13 | 3b56612a7a |
14 | 1dc298a601 |
15 | 110aee1a7d |
hex | 993a0e9a9 |
41131501993 has 2 divisors, whose sum is σ = 41131501994. Its totient is φ = 41131501992.
The previous prime is 41131501987. The next prime is 41131502017. The reversal of 41131501993 is 39910513114.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 40701852009 + 429649984 = 201747^2 + 20728^2 .
It is a cyclic number.
It is not a de Polignac number, because 41131501993 - 213 = 41131493801 is a prime.
It is not a weakly prime, because it can be changed into another prime (41131501903) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20565750996 + 20565750997.
It is an arithmetic number, because the mean of its divisors is an integer number (20565750997).
Almost surely, 241131501993 is an apocalyptic number.
It is an amenable number.
41131501993 is a deficient number, since it is larger than the sum of its proper divisors (1).
41131501993 is an equidigital number, since it uses as much as digits as its factorization.
41131501993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14580, while the sum is 37.
The spelling of 41131501993 in words is "forty-one billion, one hundred thirty-one million, five hundred one thousand, nine hundred ninety-three".
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