4113153131 has 4 divisors (see below), whose sum is σ = 4115194392. Its totient is φ = 4111111872.

The previous prime is 4113153119. The next prime is 4113153133. The reversal of 4113153131 is 1313513114.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1313513114 = 2 ⋅656756557.

It is a cyclic number.

It is not a de Polignac number, because 4113153131 - 2¹⁰ = 4113152107 is a prime.

It is a super-2 number, since 2×4113153131² = 33836057358110206322, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4113153097 and 4113153106.

It is not an unprimeable number, because it can be changed into a prime (4113153133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1017605 + ... + 1021638.

It is an arithmetic number, because the mean of its divisors is an integer number (1028798598).

Almost surely, 2^4113153131 is an apocalyptic number.

4113153131 is a deficient number, since it is larger than the sum of its proper divisors (2041261).

4113153131 is a wasteful number, since it uses less digits than its factorization.

4113153131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2041260.

The product of its digits is 540, while the sum is 23.

The square root of 4113153131 is about 64133.8688291920. The cubic root of 4113153131 is about 1602.2303700602.

Adding to 4113153131 its reverse (1313513114), we get a palindrome (5426666245).

The spelling of 4113153131 in words is "four billion, one hundred thirteen million, one hundred fifty-three thousand, one hundred thirty-one".