Base | Representation |
---|---|
bin | 111011110110101110100… |
… | …111001100010110111101 |
3 | 112120012220220022202122112 |
4 | 323312232213030112331 |
5 | 1014342330040241333 |
6 | 12425330054023405 |
7 | 603112154301626 |
oct | 73665647142675 |
9 | 15505826282575 |
10 | 4113213212093 |
11 | 1346449699567 |
12 | 565202947b65 |
13 | 23ab49c0ba6b |
14 | 10311b18aa4d |
15 | 71eda210948 |
hex | 3bdae9cc5bd |
4113213212093 has 2 divisors, whose sum is σ = 4113213212094. Its totient is φ = 4113213212092.
The previous prime is 4113213212083. The next prime is 4113213212117. The reversal of 4113213212093 is 3902123123114.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2978395994809 + 1134817217284 = 1725803^2 + 1065278^2 .
It is a cyclic number.
It is not a de Polignac number, because 4113213212093 - 212 = 4113213207997 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4113213212083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056606606046 + 2056606606047.
It is an arithmetic number, because the mean of its divisors is an integer number (2056606606047).
Almost surely, 24113213212093 is an apocalyptic number.
It is an amenable number.
4113213212093 is a deficient number, since it is larger than the sum of its proper divisors (1).
4113213212093 is an equidigital number, since it uses as much as digits as its factorization.
4113213212093 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 32.
The spelling of 4113213212093 in words is "four trillion, one hundred thirteen billion, two hundred thirteen million, two hundred twelve thousand, ninety-three".
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