41132401333 has 2 divisors, whose sum is σ = 41132401334. Its totient is φ = 41132401332.

The previous prime is 41132401309. The next prime is 41132401361. The reversal of 41132401333 is 33310423114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 21313956049 + 19818445284 = 145993^2 + 140778^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-41132401333 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 41132401298 and 41132401307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41132401393) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20566200666 + 20566200667.

It is an arithmetic number, because the mean of its divisors is an integer number (20566200667).

Almost surely, 2^41132401333 is an apocalyptic number.

It is an amenable number.

41132401333 is a deficient number, since it is larger than the sum of its proper divisors (1).

41132401333 is an equidigital number, since it uses as much as digits as its factorization.

41132401333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 41132401333 its reverse (33310423114), we get a palindrome (74442824447).

The spelling of 41132401333 in words is "forty-one billion, one hundred thirty-two million, four hundred one thousand, three hundred thirty-three".