Base | Representation |
---|---|
bin | 111011110110110000010… |
… | …001001100100001101100 |
3 | 112120012222211121112112220 |
4 | 323312300101030201230 |
5 | 1014342404144000134 |
6 | 12425332525355340 |
7 | 603112642425231 |
oct | 73666021144154 |
9 | 15505884545486 |
10 | 4113241000044 |
11 | 1346463349010 |
12 | 565210108b50 |
13 | 23ab528bac37 |
14 | 103120b41788 |
15 | 71edc89e149 |
hex | 3bdb044c86c |
4113241000044 has 48 divisors (see below), whose sum is σ = 10470237810816. Its totient is φ = 1246416451200.
The previous prime is 4113241000007. The next prime is 4113241000051. The reversal of 4113241000044 is 4400001423114.
It is a junction number, because it is equal to n+sod(n) for n = 4113240999978 and 4113241000023.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9271539 + ... + 9705045.
It is an arithmetic number, because the mean of its divisors is an integer number (218129954392).
Almost surely, 24113241000044 is an apocalyptic number.
4113241000044 is a gapful number since it is divisible by the number (44) formed by its first and last digit.
It is an amenable number.
4113241000044 is an abundant number, since it is smaller than the sum of its proper divisors (6356996810772).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4113241000044 is a wasteful number, since it uses less digits than its factorization.
4113241000044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 505406 (or 505404 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 24.
Adding to 4113241000044 its reverse (4400001423114), we get a palindrome (8513242423158).
The spelling of 4113241000044 in words is "four trillion, one hundred thirteen billion, two hundred forty-one million, forty-four", and thus it is an aban number.
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