Base | Representation |
---|---|
bin | 111011110110110011111… |
… | …101101101001111101100 |
3 | 112120020011011021110120012 |
4 | 323312303331231033230 |
5 | 1014343021032000134 |
6 | 12425343022312352 |
7 | 603114324422240 |
oct | 73666375551754 |
9 | 15506134243505 |
10 | 4113303000044 |
11 | 1346495345587 |
12 | 565228a286b8 |
13 | 23ab626b8324 |
14 | 103129080420 |
15 | 71ee30496ce |
hex | 3bdb3f6d3ec |
4113303000044 has 24 divisors (see below), whose sum is σ = 8226650251008. Its totient is φ = 1762834660560.
The previous prime is 4113302999989. The next prime is 4113303000067. The reversal of 4113303000044 is 4400003033114.
It is a junction number, because it is equal to n+sod(n) for n = 4113302999983 and 4113303000019.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8131847 + ... + 8622849.
It is an arithmetic number, because the mean of its divisors is an integer number (342777093792).
Almost surely, 24113303000044 is an apocalyptic number.
It is an amenable number.
4113303000044 is an abundant number, since it is smaller than the sum of its proper divisors (4113347250964).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4113303000044 is a wasteful number, since it uses less digits than its factorization.
4113303000044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 790205 (or 790203 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 4113303000044 its reverse (4400003033114), we get a palindrome (8513306033158).
The spelling of 4113303000044 in words is "four trillion, one hundred thirteen billion, three hundred three million, forty-four", and thus it is an aban number.
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