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4113303000141 = 33203428067749
BaseRepresentation
bin111011110110110011111…
…101101101010001001101
3112120020011011021110200210
4323312303331231101031
51014343021032001031
612425343022313033
7603114324422436
oct73666375552115
915506134243623
104113303000141
111346495345665
12565228a28779
1323ab626b839a
1410312908048d
1571ee3049746
hex3bdb3f6d44d

4113303000141 has 8 divisors (see below), whose sum is σ = 5486116284000. Its totient is φ = 2741345858192.

The previous prime is 4113303000139. The next prime is 4113303000161. The reversal of 4113303000141 is 1410003033114.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 4113303000141 - 21 = 4113303000139 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4113303000101) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 214024266 + ... + 214043483.

It is an arithmetic number, because the mean of its divisors is an integer number (685764535500).

Almost surely, 24113303000141 is an apocalyptic number.

It is an amenable number.

4113303000141 is a deficient number, since it is larger than the sum of its proper divisors (1372813283859).

4113303000141 is a wasteful number, since it uses less digits than its factorization.

4113303000141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 428070955.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 4113303000141 its reverse (1410003033114), we get a palindrome (5523306033255).

The spelling of 4113303000141 in words is "four trillion, one hundred thirteen billion, three hundred three million, one hundred forty-one", and thus it is an aban number.

Divisors: 1 3 3203 9609 428067749 1284203247 1371101000047 4113303000141