Base | Representation |
---|---|
bin | 10010101101001000001111… |
… | …10101110001110101000001 |
3 | 12101122021112211000220201012 |
4 | 21112210013311301311001 |
5 | 20342410423013111113 |
6 | 223252131000450305 |
7 | 11443522624336526 |
oct | 1126440765616501 |
9 | 171567484026635 |
10 | 41133033332033 |
11 | 1211946aa86375 |
12 | 4743a35779995 |
13 | 19c4a9ccbcb46 |
14 | a22bc6bcd14d |
15 | 4b4e70771aa8 |
hex | 256907d71d41 |
41133033332033 has 2 divisors, whose sum is σ = 41133033332034. Its totient is φ = 41133033332032.
The previous prime is 41133033331997. The next prime is 41133033332081. The reversal of 41133033332033 is 33023333033114.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 37471195162384 + 3661838169649 = 6121372^2 + 1913593^2 .
It is a cyclic number.
It is not a de Polignac number, because 41133033332033 - 222 = 41133029137729 is a prime.
It is not a weakly prime, because it can be changed into another prime (41133033332093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20566516666016 + 20566516666017.
It is an arithmetic number, because the mean of its divisors is an integer number (20566516666017).
Almost surely, 241133033332033 is an apocalyptic number.
It is an amenable number.
41133033332033 is a deficient number, since it is larger than the sum of its proper divisors (1).
41133033332033 is an equidigital number, since it uses as much as digits as its factorization.
41133033332033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52488, while the sum is 32.
Adding to 41133033332033 its reverse (33023333033114), we get a palindrome (74156366365147).
The spelling of 41133033332033 in words is "forty-one trillion, one hundred thirty-three billion, thirty-three million, three hundred thirty-two thousand, thirty-three".
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