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4113304214331 = 3131013104115833
BaseRepresentation
bin111011110110110100000…
…010010101101100111011
3112120020011020120011020210
4323312310002111230323
51014343021334324311
612425343104322203
7603114340640364
oct73666402255473
915506136504223
104113304214331
111346495aa4924
12565229313363
1323ab62a21c40
141031292b8b6b
1571ee31d93a6
hex3bdb4095b3b

4113304214331 has 16 divisors (see below), whose sum is σ = 5912113517856. Its totient is φ = 2528765327616.

The previous prime is 4113304214273. The next prime is 4113304214339. The reversal of 4113304214331 is 1334124033114.

It is not a de Polignac number, because 4113304214331 - 26 = 4113304214267 is a prime.

It is a super-3 number, since 3×41133042143313 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (4113304214339) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 52018410 + ... + 52097423.

It is an arithmetic number, because the mean of its divisors is an integer number (369507094866).

Almost surely, 24113304214331 is an apocalyptic number.

4113304214331 is a deficient number, since it is larger than the sum of its proper divisors (1798809303525).

4113304214331 is a wasteful number, since it uses less digits than its factorization.

4113304214331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 104116862.

The product of its (nonzero) digits is 10368, while the sum is 30.

Adding to 4113304214331 its reverse (1334124033114), we get a palindrome (5447428247445).

The spelling of 4113304214331 in words is "four trillion, one hundred thirteen billion, three hundred four million, two hundred fourteen thousand, three hundred thirty-one".

Divisors: 1 3 13 39 1013 3039 13169 39507 104115833 312347499 1353505829 4060517487 105469338829 316408016487 1371101404777 4113304214331