Base | Representation |
---|---|
bin | 111011110110110100000… |
… | …010010101101100111011 |
3 | 112120020011020120011020210 |
4 | 323312310002111230323 |
5 | 1014343021334324311 |
6 | 12425343104322203 |
7 | 603114340640364 |
oct | 73666402255473 |
9 | 15506136504223 |
10 | 4113304214331 |
11 | 1346495aa4924 |
12 | 565229313363 |
13 | 23ab62a21c40 |
14 | 1031292b8b6b |
15 | 71ee31d93a6 |
hex | 3bdb4095b3b |
4113304214331 has 16 divisors (see below), whose sum is σ = 5912113517856. Its totient is φ = 2528765327616.
The previous prime is 4113304214273. The next prime is 4113304214339. The reversal of 4113304214331 is 1334124033114.
It is not a de Polignac number, because 4113304214331 - 26 = 4113304214267 is a prime.
It is a super-3 number, since 3×41133042143313 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (4113304214339) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 52018410 + ... + 52097423.
It is an arithmetic number, because the mean of its divisors is an integer number (369507094866).
Almost surely, 24113304214331 is an apocalyptic number.
4113304214331 is a deficient number, since it is larger than the sum of its proper divisors (1798809303525).
4113304214331 is a wasteful number, since it uses less digits than its factorization.
4113304214331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 104116862.
The product of its (nonzero) digits is 10368, while the sum is 30.
Adding to 4113304214331 its reverse (1334124033114), we get a palindrome (5447428247445).
The spelling of 4113304214331 in words is "four trillion, one hundred thirteen billion, three hundred four million, two hundred fourteen thousand, three hundred thirty-one".
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