Base | Representation |
---|---|
bin | 10010101101001000011000… |
… | …11011001010101111111111 |
3 | 12101122021202011202100202201 |
4 | 21112210030123022233333 |
5 | 20342411102210223203 |
6 | 223252142345132331 |
7 | 11443524550143652 |
oct | 1126441433125777 |
9 | 171567664670681 |
10 | 41133110242303 |
11 | 121194aa437182 |
12 | 4743a5748a0a7 |
13 | 19c4ab2c0aa91 |
14 | a22bd30cd899 |
15 | 4b4e773b4e1d |
hex | 25690c6cabff |
41133110242303 has 2 divisors, whose sum is σ = 41133110242304. Its totient is φ = 41133110242302.
The previous prime is 41133110242283. The next prime is 41133110242313. The reversal of 41133110242303 is 30324201133114.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41133110242303 - 245 = 5948738153471 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41133110242313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20566555121151 + 20566555121152.
It is an arithmetic number, because the mean of its divisors is an integer number (20566555121152).
Almost surely, 241133110242303 is an apocalyptic number.
41133110242303 is a deficient number, since it is larger than the sum of its proper divisors (1).
41133110242303 is an equidigital number, since it uses as much as digits as its factorization.
41133110242303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 41133110242303 its reverse (30324201133114), we get a palindrome (71457311375417).
The spelling of 41133110242303 in words is "forty-one trillion, one hundred thirty-three billion, one hundred ten million, two hundred forty-two thousand, three hundred three".
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