Base | Representation |
---|---|
bin | 111011110110110101110… |
… | …100000101111110100111 |
3 | 112120020020022200011121200 |
4 | 323312311310011332213 |
5 | 1014343102003044333 |
6 | 12425350051413543 |
7 | 603115152256242 |
oct | 73666564057647 |
9 | 15506208604550 |
10 | 4113334034343 |
11 | 1346500912066 |
12 | 5652372b42b3 |
13 | 23ab68c63011 |
14 | 10312d23c259 |
15 | 71ee5b29c13 |
hex | 3bdb5d05fa7 |
4113334034343 has 6 divisors (see below), whose sum is σ = 5941482494064. Its totient is φ = 2742222689556.
The previous prime is 4113334034287. The next prime is 4113334034377. The reversal of 4113334034343 is 3434304333114.
4113334034343 is a `hidden beast` number, since 41 + 133 + 3 + 403 + 43 + 43 = 666.
It is not a de Polignac number, because 4113334034343 - 217 = 4113333903271 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4113334034298 and 4113334034307.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4113334034743) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 228518557455 + ... + 228518557472.
It is an arithmetic number, because the mean of its divisors is an integer number (990247082344).
Almost surely, 24113334034343 is an apocalyptic number.
4113334034343 is a deficient number, since it is larger than the sum of its proper divisors (1828148459721).
4113334034343 is a wasteful number, since it uses less digits than its factorization.
4113334034343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 457037114933 (or 457037114930 counting only the distinct ones).
The product of its (nonzero) digits is 186624, while the sum is 36.
Adding to 4113334034343 its reverse (3434304333114), we get a palindrome (7547638367457).
The spelling of 4113334034343 in words is "four trillion, one hundred thirteen billion, three hundred thirty-four million, thirty-four thousand, three hundred forty-three".
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