4113340102121 has 4 divisors (see below), whose sum is σ = 4246028492544. Its totient is φ = 3980651711700.

The previous prime is 4113340102117. The next prime is 4113340102153. The reversal of 4113340102121 is 1212010433114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4113340102121 - 2² = 4113340102117 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (4113340102021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66344195165 + ... + 66344195226.

It is an arithmetic number, because the mean of its divisors is an integer number (1061507123136).

Almost surely, 2^{4113340102121} is an apocalyptic number.

It is an amenable number.

4113340102121 is a deficient number, since it is larger than the sum of its proper divisors (132688390423).

4113340102121 is a wasteful number, since it uses less digits than its factorization.

4113340102121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 132688390422.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 4113340102121 its reverse (1212010433114), we get a palindrome (5325350535235).

The spelling of 4113340102121 in words is "four trillion, one hundred thirteen billion, three hundred forty million, one hundred two thousand, one hundred twenty-one".