Base | Representation |
---|---|
bin | 111011110110110110001… |
… | …011110001011000100001 |
3 | 112120020020202100112011012 |
4 | 323312312023301120201 |
5 | 1014343110100211231 |
6 | 12425350432430305 |
7 | 603115256110604 |
oct | 73666613613041 |
9 | 15506222315135 |
10 | 4113340241441 |
11 | 13465043715a2 |
12 | 5652393a8395 |
13 | 23ab6a327362 |
14 | 10312ddb633b |
15 | 71ee6453e2b |
hex | 3bdb62f1621 |
4113340241441 has 32 divisors (see below), whose sum is σ = 4418046996480. Its totient is φ = 3816015630336.
The previous prime is 4113340241429. The next prime is 4113340241531. The reversal of 4113340241441 is 1441420433114.
It is a cyclic number.
It is not a de Polignac number, because 4113340241441 - 218 = 4113339979297 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4113340241398 and 4113340241407.
It is not an unprimeable number, because it can be changed into a prime (4113340241341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 312011936 + ... + 312025118.
It is an arithmetic number, because the mean of its divisors is an integer number (138063968640).
Almost surely, 24113340241441 is an apocalyptic number.
It is an amenable number.
4113340241441 is a deficient number, since it is larger than the sum of its proper divisors (304706755039).
4113340241441 is a wasteful number, since it uses less digits than its factorization.
4113340241441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14153.
The product of its (nonzero) digits is 18432, while the sum is 32.
Adding to 4113340241441 its reverse (1441420433114), we get a palindrome (5554760674555).
The spelling of 4113340241441 in words is "four trillion, one hundred thirteen billion, three hundred forty million, two hundred forty-one thousand, four hundred forty-one".
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