411334034212949 has 2 divisors, whose sum is σ = 411334034212950. Its totient is φ = 411334034212948.

The previous prime is 411334034212921. The next prime is 411334034212963. The reversal of 411334034212949 is 949212430433114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 274591180648849 + 136742853564100 = 16570793^2 + 11693710^2 .

It is a cyclic number.

It is not a de Polignac number, because 411334034212949 - 2³² = 411329739245653 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 411334034212897 and 411334034212906.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (411334034212349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205667017106474 + 205667017106475.

It is an arithmetic number, because the mean of its divisors is an integer number (205667017106475).

Almost surely, 2^{411334034212949} is an apocalyptic number.

It is an amenable number.

411334034212949 is a deficient number, since it is larger than the sum of its proper divisors (1).

411334034212949 is an equidigital number, since it uses as much as digits as its factorization.

411334034212949 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2239488, while the sum is 50.

The spelling of 411334034212949 in words is "four hundred eleven trillion, three hundred thirty-four billion, thirty-four million, two hundred twelve thousand, nine hundred forty-nine".