Base | Representation |
---|---|
bin | 111011110110110110111… |
… | …111111010010000001111 |
3 | 112120020021201001220212211 |
4 | 323312312333322100033 |
5 | 1014343122100044023 |
6 | 12425352041411251 |
7 | 603115513224514 |
oct | 73666677722017 |
9 | 15506251056784 |
10 | 4113353909263 |
11 | 1346511057415 |
12 | 565241a99b27 |
13 | 23ab70101521 |
14 | 103131b3330b |
15 | 71ee7753a0d |
hex | 3bdb6ffa40f |
4113353909263 has 8 divisors (see below), whose sum is σ = 4119121566560. Its totient is φ = 4107586554720.
The previous prime is 4113353909179. The next prime is 4113353909299. The reversal of 4113353909263 is 3629093533114.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4113353909263 - 213 = 4113353901071 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4113353909963) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 51825253 + ... + 51904561.
It is an arithmetic number, because the mean of its divisors is an integer number (514890195820).
Almost surely, 24113353909263 is an apocalyptic number.
4113353909263 is a deficient number, since it is larger than the sum of its proper divisors (5767657297).
4113353909263 is an equidigital number, since it uses as much as digits as its factorization.
4113353909263 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 151377.
The product of its (nonzero) digits is 1574640, while the sum is 49.
The spelling of 4113353909263 in words is "four trillion, one hundred thirteen billion, three hundred fifty-three million, nine hundred nine thousand, two hundred sixty-three".
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