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41134103411309 is a prime number
BaseRepresentation
bin10010101101001010001111…
…00111110011101001101101
312101122101022101120120111222
421112211013213303221231
520342420120433130214
6223252425104153125
711443561300014266
oct1126450747635155
9171571271516458
1041134103411309
111211996a014807
1247440940087a5
1319c4c108c594c
14a22c88d7d96d
154b4ed469738e
hex2569479f3a6d

41134103411309 has 2 divisors, whose sum is σ = 41134103411310. Its totient is φ = 41134103411308.

The previous prime is 41134103411293. The next prime is 41134103411363. The reversal of 41134103411309 is 90311430143114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 39127489508809 + 2006613902500 = 6255197^2 + 1416550^2 .

It is a cyclic number.

It is not a de Polignac number, because 41134103411309 - 24 = 41134103411293 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41134103411389) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20567051705654 + 20567051705655.

It is an arithmetic number, because the mean of its divisors is an integer number (20567051705655).

Almost surely, 241134103411309 is an apocalyptic number.

It is an amenable number.

41134103411309 is a deficient number, since it is larger than the sum of its proper divisors (1).

41134103411309 is an equidigital number, since it uses as much as digits as its factorization.

41134103411309 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 35.

The spelling of 41134103411309 in words is "forty-one trillion, one hundred thirty-four billion, one hundred three million, four hundred eleven thousand, three hundred nine".