Base | Representation |
---|---|
bin | 10010101101001010001111… |
… | …00111110011101001101101 |
3 | 12101122101022101120120111222 |
4 | 21112211013213303221231 |
5 | 20342420120433130214 |
6 | 223252425104153125 |
7 | 11443561300014266 |
oct | 1126450747635155 |
9 | 171571271516458 |
10 | 41134103411309 |
11 | 1211996a014807 |
12 | 47440940087a5 |
13 | 19c4c108c594c |
14 | a22c88d7d96d |
15 | 4b4ed469738e |
hex | 2569479f3a6d |
41134103411309 has 2 divisors, whose sum is σ = 41134103411310. Its totient is φ = 41134103411308.
The previous prime is 41134103411293. The next prime is 41134103411363. The reversal of 41134103411309 is 90311430143114.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 39127489508809 + 2006613902500 = 6255197^2 + 1416550^2 .
It is a cyclic number.
It is not a de Polignac number, because 41134103411309 - 24 = 41134103411293 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41134103411389) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20567051705654 + 20567051705655.
It is an arithmetic number, because the mean of its divisors is an integer number (20567051705655).
Almost surely, 241134103411309 is an apocalyptic number.
It is an amenable number.
41134103411309 is a deficient number, since it is larger than the sum of its proper divisors (1).
41134103411309 is an equidigital number, since it uses as much as digits as its factorization.
41134103411309 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 35.
The spelling of 41134103411309 in words is "forty-one trillion, one hundred thirty-four billion, one hundred three million, four hundred eleven thousand, three hundred nine".
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