Base | Representation |
---|---|
bin | 101110110000111011001011… |
… | …0101101011001011110100100 |
3 | 1222221110010212200012220010112 |
4 | 1131201312112231121132210 |
5 | 412403431343404314134 |
6 | 4014505004545112152 |
7 | 152433440321066312 |
oct | 13541662655313644 |
9 | 1887403780186115 |
10 | 411344431323044 |
11 | 10a08121483349a |
12 | 3a175381928658 |
13 | 1486a7c89321ab |
14 | 7381268c3d0b2 |
15 | 328502ca031ce |
hex | 1761d96b597a4 |
411344431323044 has 12 divisors (see below), whose sum is σ = 722589837535104. Its totient is φ = 204890192027304.
The previous prime is 411344431323037. The next prime is 411344431323053. The reversal of 411344431323044 is 440323134443114.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 411344431322992 and 411344431323010.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 195505907372 + ... + 195505909475.
It is an arithmetic number, because the mean of its divisors is an integer number (60215819794592).
Almost surely, 2411344431323044 is an apocalyptic number.
It is an amenable number.
411344431323044 is a deficient number, since it is larger than the sum of its proper divisors (311245406212060).
411344431323044 is a wasteful number, since it uses less digits than its factorization.
411344431323044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 391011817114 (or 391011817112 counting only the distinct ones).
The product of its (nonzero) digits is 663552, while the sum is 41.
Adding to 411344431323044 its reverse (440323134443114), we get a palindrome (851667565766158).
The spelling of 411344431323044 in words is "four hundred eleven trillion, three hundred forty-four billion, four hundred thirty-one million, three hundred twenty-three thousand, forty-four".
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