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41134622423047 is a prime number
BaseRepresentation
bin10010101101001011001101…
…00011101011100000000111
312101122102122120012002202221
421112211212203223200013
520342422201320014142
6223252552404313211
711443610201363116
oct1126454643534007
9171572576162687
1041134622423047
111211a105a86a2a
1247441b99a2807
1319c4c942a639a
14a22cd7c83c7d
154b5015018767
hex2569668eb807

41134622423047 has 2 divisors, whose sum is σ = 41134622423048. Its totient is φ = 41134622423046.

The previous prime is 41134622422961. The next prime is 41134622423107. The reversal of 41134622423047 is 74032422643114.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 41134622423047 - 239 = 40584866609159 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 41134622422994 and 41134622423012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41134622463047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20567311211523 + 20567311211524.

It is an arithmetic number, because the mean of its divisors is an integer number (20567311211524).

Almost surely, 241134622423047 is an apocalyptic number.

41134622423047 is a deficient number, since it is larger than the sum of its proper divisors (1).

41134622423047 is an equidigital number, since it uses as much as digits as its factorization.

41134622423047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 774144, while the sum is 43.

The spelling of 41134622423047 in words is "forty-one trillion, one hundred thirty-four billion, six hundred twenty-two million, four hundred twenty-three thousand, forty-seven".