411354941 has 2 divisors, whose sum is σ = 411354942. Its totient is φ = 411354940.

The previous prime is 411354907. The next prime is 411354949. The reversal of 411354941 is 149453114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 330876100 + 80478841 = 18190^2 + 8971^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-411354941 is a prime.

It is a super-2 number, since 2×411354941² = 338425774970226962, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 411354898 and 411354907.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (411354949) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205677470 + 205677471.

It is an arithmetic number, because the mean of its divisors is an integer number (205677471).

Almost surely, 2^411354941 is an apocalyptic number.

It is an amenable number.

411354941 is a deficient number, since it is larger than the sum of its proper divisors (1).

411354941 is an equidigital number, since it uses as much as digits as its factorization.

411354941 is an evil number, because the sum of its binary digits is even.

The product of its digits is 8640, while the sum is 32.

The square root of 411354941 is about 20281.8870177309. The cubic root of 411354941 is about 743.7133421096.

The spelling of 411354941 in words is "four hundred eleven million, three hundred fifty-four thousand, nine hundred forty-one".