Base | Representation |
---|---|
bin | 111011110111011100111… |
… | …111100101011011011101 |
3 | 112120021221010112200101201 |
4 | 323313130333211123131 |
5 | 1014400423241430143 |
6 | 12425535212235501 |
7 | 603140353365244 |
oct | 73673477453335 |
9 | 15507833480351 |
10 | 4113991358173 |
11 | 13468089631a4 |
12 | 56539b46bb91 |
13 | 23ac421ac728 |
14 | 10319266795b |
15 | 720336bc64d |
hex | 3bddcfe56dd |
4113991358173 has 2 divisors, whose sum is σ = 4113991358174. Its totient is φ = 4113991358172.
The previous prime is 4113991358153. The next prime is 4113991358189. The reversal of 4113991358173 is 3718531993114.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2144622589209 + 1969368768964 = 1464453^2 + 1403342^2 .
It is a cyclic number.
It is not a de Polignac number, because 4113991358173 - 237 = 3976552404701 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4113991358123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056995679086 + 2056995679087.
It is an arithmetic number, because the mean of its divisors is an integer number (2056995679087).
Almost surely, 24113991358173 is an apocalyptic number.
It is an amenable number.
4113991358173 is a deficient number, since it is larger than the sum of its proper divisors (1).
4113991358173 is an equidigital number, since it uses as much as digits as its factorization.
4113991358173 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2449440, while the sum is 55.
The spelling of 4113991358173 in words is "four trillion, one hundred thirteen billion, nine hundred ninety-one million, three hundred fifty-eight thousand, one hundred seventy-three".
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