Base | Representation |
---|---|
bin | 111011110111011101101… |
… | …101000010111011011001 |
3 | 112120021221221222010212111 |
4 | 323313131231002323121 |
5 | 1014400434314303411 |
6 | 12425540315512321 |
7 | 603140556601501 |
oct | 73673555027331 |
9 | 15507857863774 |
10 | 4114003275481 |
11 | 1346814662910 |
12 | 5653a34586a1 |
13 | 23ac447c2ba8 |
14 | 10319408aa01 |
15 | 72034773721 |
hex | 3bdddb42ed9 |
4114003275481 has 4 divisors (see below), whose sum is σ = 4488003573264. Its totient is φ = 3740002977700.
The previous prime is 4114003275479. The next prime is 4114003275523. The reversal of 4114003275481 is 1845723004114.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 4114003275481 - 21 = 4114003275479 is a prime.
It is a super-2 number, since 2×41140032754812 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4114003275281) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 187000148875 + ... + 187000148896.
It is an arithmetic number, because the mean of its divisors is an integer number (1122000893316).
Almost surely, 24114003275481 is an apocalyptic number.
It is an amenable number.
4114003275481 is a deficient number, since it is larger than the sum of its proper divisors (374000297783).
4114003275481 is a wasteful number, since it uses less digits than its factorization.
4114003275481 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 374000297782.
The product of its (nonzero) digits is 107520, while the sum is 40.
Adding to 4114003275481 its reverse (1845723004114), we get a palindrome (5959726279595).
The spelling of 4114003275481 in words is "four trillion, one hundred fourteen billion, three million, two hundred seventy-five thousand, four hundred eighty-one".
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