411401300343 has 32 divisors (see below), whose sum is σ = 618630980352. Its totient is φ = 241024896000.

The previous prime is 411401300333. The next prime is 411401300371. The reversal of 411401300343 is 343003104114.

It is not a de Polignac number, because 411401300343 - 2⁸ = 411401300087 is a prime.

It is a super-2 number, since 2×411401300343² (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (411401300333) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1356808 + ... + 1632093.

It is an arithmetic number, because the mean of its divisors is an integer number (19332218136).

Almost surely, 2^411401300343 is an apocalyptic number.

411401300343 is a gapful number since it is divisible by the number (43) formed by its first and last digit.

411401300343 is a deficient number, since it is larger than the sum of its proper divisors (207229680009).

411401300343 is a wasteful number, since it uses less digits than its factorization.

411401300343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2989055.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 411401300343 its reverse (343003104114), we get a palindrome (754404404457).

The spelling of 411401300343 in words is "four hundred eleven billion, four hundred one million, three hundred thousand, three hundred forty-three".