Base | Representation |
---|---|
bin | 10010101101010101111110… |
… | …00001010100000010010011 |
3 | 12101122222120022122100110121 |
4 | 21112222333001110002103 |
5 | 20343021020244203210 |
6 | 223255350051211111 |
7 | 11444203334234113 |
oct | 1126527701240223 |
9 | 171588508570417 |
10 | 41140401553555 |
11 | 12121601170247 |
12 | 47453512a6a97 |
13 | 19c56a568ba35 |
14 | a232c55db043 |
15 | 4b52525736da |
hex | 256abf054093 |
41140401553555 has 4 divisors (see below), whose sum is σ = 49368481864272. Its totient is φ = 32912321242840.
The previous prime is 41140401553553. The next prime is 41140401553607. The reversal of 41140401553555 is 55535510404114.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 41140401553555 - 21 = 41140401553553 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (41140401553553) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4114040155351 + ... + 4114040155360.
It is an arithmetic number, because the mean of its divisors is an integer number (12342120466068).
Almost surely, 241140401553555 is an apocalyptic number.
41140401553555 is a deficient number, since it is larger than the sum of its proper divisors (8228080310717).
41140401553555 is an equidigital number, since it uses as much as digits as its factorization.
41140401553555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8228080310716.
The product of its (nonzero) digits is 600000, while the sum is 43.
Adding to 41140401553555 its reverse (55535510404114), we get a palindrome (96675911957669).
The spelling of 41140401553555 in words is "forty-one trillion, one hundred forty billion, four hundred one million, five hundred fifty-three thousand, five hundred fifty-five".
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