Base | Representation |
---|---|
bin | 111011110111100000101… |
… | …011111010011010101010 |
3 | 112120022002110010011111100 |
4 | 323313200223322122222 |
5 | 1014401040121410442 |
6 | 12425545304142230 |
7 | 603142035102210 |
oct | 73674053723252 |
9 | 15508073104440 |
10 | 4114053310122 |
11 | 134683a927658 |
12 | 5653b8167976 |
13 | 23ac51c90ca2 |
14 | 10319a992cb0 |
15 | 72038d5884c |
hex | 3bde0afa6aa |
4114053310122 has 24 divisors (see below), whose sum is σ = 10187179625376. Its totient is φ = 1175443802856.
The previous prime is 4114053310117. The next prime is 4114053310123. The reversal of 4114053310122 is 2210133504114.
4114053310122 is a `hidden beast` number, since 4 + 1 + 1 + 4 + 0 + 533 + 1 + 0 + 122 = 666.
It is not an unprimeable number, because it can be changed into a prime (4114053310123) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 16325608248 + ... + 16325608499.
It is an arithmetic number, because the mean of its divisors is an integer number (424465817724).
Almost surely, 24114053310122 is an apocalyptic number.
4114053310122 is a gapful number since it is divisible by the number (42) formed by its first and last digit.
4114053310122 is an abundant number, since it is smaller than the sum of its proper divisors (6073126315254).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4114053310122 is a wasteful number, since it uses less digits than its factorization.
4114053310122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32651216762 (or 32651216759 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 27.
Adding to 4114053310122 its reverse (2210133504114), we get a palindrome (6324186814236).
The spelling of 4114053310122 in words is "four trillion, one hundred fourteen billion, fifty-three million, three hundred ten thousand, one hundred twenty-two".
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