Base | Representation |
---|---|
bin | 1011111110010100001… |
… | …00010010000010100111 |
3 | 1110022221000021201010020 |
4 | 11333022010102002213 |
5 | 23220032433410343 |
6 | 513000003130223 |
7 | 41503113261411 |
oct | 5771204220247 |
9 | 1408830251106 |
10 | 411412013223 |
11 | 14952a3a0892 |
12 | 67899073973 |
13 | 2ca46a222a3 |
14 | 15caba839b1 |
15 | aa7d720b83 |
hex | 5fca1120a7 |
411412013223 has 4 divisors (see below), whose sum is σ = 548549350968. Its totient is φ = 274274675480.
The previous prime is 411412013167. The next prime is 411412013281. The reversal of 411412013223 is 322310214114.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 411412013223 - 225 = 411378458791 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 411412013193 and 411412013202.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (411412013123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68568668868 + ... + 68568668873.
It is an arithmetic number, because the mean of its divisors is an integer number (137137337742).
Almost surely, 2411412013223 is an apocalyptic number.
411412013223 is a deficient number, since it is larger than the sum of its proper divisors (137137337745).
411412013223 is a wasteful number, since it uses less digits than its factorization.
411412013223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 137137337744.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 411412013223 its reverse (322310214114), we get a palindrome (733722227337).
The spelling of 411412013223 in words is "four hundred eleven billion, four hundred twelve million, thirteen thousand, two hundred twenty-three".
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