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41141212131 = 313713737377
BaseRepresentation
bin100110010100001101…
…010001001111100011
310221012012110010020110
4212110031101033203
51133224122242011
630522222542403
72654342350605
oct462415211743
9127165403213
1041141212131
11164a2161668
127b82137a03
133b58632706
141dc3d97175
15110bcadba6
hex9943513e3

41141212131 has 4 divisors (see below), whose sum is σ = 54854949512. Its totient is φ = 27427474752.

The previous prime is 41141212127. The next prime is 41141212153. The reversal of 41141212131 is 13121214114.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 41141212131 - 22 = 41141212127 is a prime.

It is a super-2 number, since 2×411412121312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 41141212098 and 41141212107.

It is not an unprimeable number, because it can be changed into a prime (41141212171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6856868686 + ... + 6856868691.

It is an arithmetic number, because the mean of its divisors is an integer number (13713737378).

Almost surely, 241141212131 is an apocalyptic number.

41141212131 is a deficient number, since it is larger than the sum of its proper divisors (13713737381).

41141212131 is a wasteful number, since it uses less digits than its factorization.

41141212131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13713737380.

The product of its digits is 192, while the sum is 21.

Adding to 41141212131 its reverse (13121214114), we get a palindrome (54262426245).

The spelling of 41141212131 in words is "forty-one billion, one hundred forty-one million, two hundred twelve thousand, one hundred thirty-one".

Divisors: 1 3 13713737377 41141212131