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41142013271 is a prime number
BaseRepresentation
bin100110010100010000…
…010100110101010111
310221012020221211012022
4212110100110311113
51133224323411041
630522252043355
72654352225362
oct462420246527
9127166854168
1041142013271
11164a2659567
127b8246355b
133b58853268
141dc41250d9
15110bdbb24b
hex994414d57

41142013271 has 2 divisors, whose sum is σ = 41142013272. Its totient is φ = 41142013270.

The previous prime is 41142013247. The next prime is 41142013303. The reversal of 41142013271 is 17231024114.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41142013271 is a prime.

It is a super-2 number, since 2×411420132712 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 41142013271.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41142010271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20571006635 + 20571006636.

It is an arithmetic number, because the mean of its divisors is an integer number (20571006636).

Almost surely, 241142013271 is an apocalyptic number.

41142013271 is a deficient number, since it is larger than the sum of its proper divisors (1).

41142013271 is an equidigital number, since it uses as much as digits as its factorization.

41142013271 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1344, while the sum is 26.

Adding to 41142013271 its reverse (17231024114), we get a palindrome (58373037385).

The spelling of 41142013271 in words is "forty-one billion, one hundred forty-two million, thirteen thousand, two hundred seventy-one".