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411421320403 = 1553712647993
BaseRepresentation
bin1011111110010101001…
…11110010010011010011
31110022221122210120011121
411333022213302103103
523220042324223103
6513000534423111
741503255344142
oct5771247622323
91408848716147
10411421320403
11149534678475
12678a0201a97
132ca489306b2
1415cacdc7759
15aa7e45d6bd
hex5fca9f24d3

411421320403 has 4 divisors (see below), whose sum is σ = 411424123768. Its totient is φ = 411418517040.

The previous prime is 411421320341. The next prime is 411421320413. The reversal of 411421320403 is 304023124114.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 304023124114 = 2152011562057.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-411421320403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (411421320413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1168626 + ... + 1479367.

It is an arithmetic number, because the mean of its divisors is an integer number (102856030942).

Almost surely, 2411421320403 is an apocalyptic number.

411421320403 is a deficient number, since it is larger than the sum of its proper divisors (2803365).

411421320403 is a wasteful number, since it uses less digits than its factorization.

411421320403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2803364.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 411421320403 its reverse (304023124114), we get a palindrome (715444444517).

The spelling of 411421320403 in words is "four hundred eleven billion, four hundred twenty-one million, three hundred twenty thousand, four hundred three".

Divisors: 1 155371 2647993 411421320403