Base | Representation |
---|---|
bin | 1011111110010101100… |
… | …11100100101110001111 |
3 | 1110022221212121120000001 |
4 | 11333022303210232033 |
5 | 23220044122114021 |
6 | 513001124545131 |
7 | 41503323534202 |
oct | 5771263445617 |
9 | 1408855546001 |
10 | 411424410511 |
11 | 149536399084 |
12 | 678a12521a7 |
13 | 2ca4947306a |
14 | 15cad58d939 |
15 | aa7e86e091 |
hex | 5fcace4b8f |
411424410511 has 2 divisors, whose sum is σ = 411424410512. Its totient is φ = 411424410510.
The previous prime is 411424410433. The next prime is 411424410533. The reversal of 411424410511 is 115014424114.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 411424410511 - 211 = 411424408463 is a prime.
It is a super-2 number, since 2×4114244105112 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 411424410511.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (411424410581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205712205255 + 205712205256.
It is an arithmetic number, because the mean of its divisors is an integer number (205712205256).
Almost surely, 2411424410511 is an apocalyptic number.
411424410511 is a deficient number, since it is larger than the sum of its proper divisors (1).
411424410511 is an equidigital number, since it uses as much as digits as its factorization.
411424410511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2560, while the sum is 28.
Adding to 411424410511 its reverse (115014424114), we get a palindrome (526438834625).
The spelling of 411424410511 in words is "four hundred eleven billion, four hundred twenty-four million, four hundred ten thousand, five hundred eleven".
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