Base | Representation |
---|---|
bin | 10010101101011011000001… |
… | …01000101111011110011101 |
3 | 12101200020120021202012000102 |
4 | 21112231200220233132131 |
5 | 20343042043413140331 |
6 | 223300515111310445 |
7 | 11444330460312032 |
oct | 1126554050573635 |
9 | 171606507665012 |
10 | 41143113021341 |
11 | 1212277277a111 |
12 | 474598937b425 |
13 | 19c5a1835c146 |
14 | a234a1777389 |
15 | 4b53606214cb |
hex | 256b60a2f79d |
41143113021341 has 2 divisors, whose sum is σ = 41143113021342. Its totient is φ = 41143113021340.
The previous prime is 41143113021287. The next prime is 41143113021349. The reversal of 41143113021341 is 14312031134114.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 41136381475225 + 6731546116 = 6413765^2 + 82046^2 .
It is a cyclic number.
It is not a de Polignac number, because 41143113021341 - 26 = 41143113021277 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41143113021349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20571556510670 + 20571556510671.
It is an arithmetic number, because the mean of its divisors is an integer number (20571556510671).
Almost surely, 241143113021341 is an apocalyptic number.
It is an amenable number.
41143113021341 is a deficient number, since it is larger than the sum of its proper divisors (1).
41143113021341 is an equidigital number, since it uses as much as digits as its factorization.
41143113021341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 29.
Adding to 41143113021341 its reverse (14312031134114), we get a palindrome (55455144155455).
The spelling of 41143113021341 in words is "forty-one trillion, one hundred forty-three billion, one hundred thirteen million, twenty-one thousand, three hundred forty-one".
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