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4114313010407 is a prime number
BaseRepresentation
bin111011110111110000001…
…010100101110011100111
3112120022202112210022022102
4323313300022211303213
51014402103112313112
612430031142322315
7603151340364665
oct73676012456347
915508675708272
104114313010407
111346963486296
1256546b12939b
1323ac93a1b9b2
141031c3275c35
1572051a56bc2
hex3bdf02a5ce7

4114313010407 has 2 divisors, whose sum is σ = 4114313010408. Its totient is φ = 4114313010406.

The previous prime is 4114313010371. The next prime is 4114313010433. The reversal of 4114313010407 is 7040103134114.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4114313010407 - 212 = 4114313006311 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4114313010407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4114313510407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2057156505203 + 2057156505204.

It is an arithmetic number, because the mean of its divisors is an integer number (2057156505204).

Almost surely, 24114313010407 is an apocalyptic number.

4114313010407 is a deficient number, since it is larger than the sum of its proper divisors (1).

4114313010407 is an equidigital number, since it uses as much as digits as its factorization.

4114313010407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 29.

The spelling of 4114313010407 in words is "four trillion, one hundred fourteen billion, three hundred thirteen million, ten thousand, four hundred seven".