Base | Representation |
---|---|
bin | 1011111110010110011… |
… | …01111110001001100111 |
3 | 1110022222100122010022111 |
4 | 11333023031332021213 |
5 | 23220102410033112 |
6 | 513001533141451 |
7 | 41503436414626 |
oct | 5771315761147 |
9 | 1408870563274 |
10 | 411431330407 |
11 | 14953a2950a9 |
12 | 678a362a887 |
13 | 2ca4aa26986 |
14 | 15cb04716bd |
15 | aa802895a7 |
hex | 5fcb37e267 |
411431330407 has 2 divisors, whose sum is σ = 411431330408. Its totient is φ = 411431330406.
The previous prime is 411431330381. The next prime is 411431330417. The reversal of 411431330407 is 704033134114.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 411431330407 - 211 = 411431328359 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (411431330417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205715665203 + 205715665204.
It is an arithmetic number, because the mean of its divisors is an integer number (205715665204).
Almost surely, 2411431330407 is an apocalyptic number.
411431330407 is a deficient number, since it is larger than the sum of its proper divisors (1).
411431330407 is an equidigital number, since it uses as much as digits as its factorization.
411431330407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 31.
The spelling of 411431330407 in words is "four hundred eleven billion, four hundred thirty-one million, three hundred thirty thousand, four hundred seven".
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