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41143144353253 is a prime number
BaseRepresentation
bin10010101101011011000101…
…00000010000110111100101
312101200020122110201000022121
421112231202200100313211
520343042124423301003
6223300522151025541
711444331320525515
oct1126554240206745
9171606573630277
1041143144353253
111212278942a258
12474599796b2b1
1319c5a219ac437
14a234a59b1845
154b536325ecbd
hex256b62810de5

41143144353253 has 2 divisors, whose sum is σ = 41143144353254. Its totient is φ = 41143144353252.

The previous prime is 41143144353151. The next prime is 41143144353293. The reversal of 41143144353253 is 35235344134114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 26765950710724 + 14377193642529 = 5173582^2 + 3791727^2 .

It is a cyclic number.

It is not a de Polignac number, because 41143144353253 - 217 = 41143144222181 is a prime.

It is a super-2 number, since 2×411431443532532 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41143144353293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20571572176626 + 20571572176627.

It is an arithmetic number, because the mean of its divisors is an integer number (20571572176627).

Almost surely, 241143144353253 is an apocalyptic number.

It is an amenable number.

41143144353253 is a deficient number, since it is larger than the sum of its proper divisors (1).

41143144353253 is an equidigital number, since it uses as much as digits as its factorization.

41143144353253 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1036800, while the sum is 43.

Adding to 41143144353253 its reverse (35235344134114), we get a palindrome (76378488487367).

The spelling of 41143144353253 in words is "forty-one trillion, one hundred forty-three billion, one hundred forty-four million, three hundred fifty-three thousand, two hundred fifty-three".