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4114434433 is a prime number
BaseRepresentation
bin1111010100111101…
…0100100110000001
3101121202000220222111
43311033110212001
531411243400213
61520134335321
7203650054444
oct36517244601
911552026874
104114434433
11182154453a
12969aba541
1350754a2b5
142b062165b
1519132ba3d
hexf53d4981

4114434433 has 2 divisors, whose sum is σ = 4114434434. Its totient is φ = 4114434432.

The previous prime is 4114434413. The next prime is 4114434437. The reversal of 4114434433 is 3344344114.

It is a happy number.

4114434433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4012969104 + 101465329 = 63348^2 + 10073^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4114434433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4114434395 and 4114434404.

It is not a weakly prime, because it can be changed into another prime (4114434437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2057217216 + 2057217217.

It is an arithmetic number, because the mean of its divisors is an integer number (2057217217).

Almost surely, 24114434433 is an apocalyptic number.

It is an amenable number.

4114434433 is a deficient number, since it is larger than the sum of its proper divisors (1).

4114434433 is an equidigital number, since it uses as much as digits as its factorization.

4114434433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 27648, while the sum is 31.

The square root of 4114434433 is about 64143.8573286640. The cubic root of 4114434433 is about 1602.3967248231.

Adding to 4114434433 its reverse (3344344114), we get a palindrome (7458778547).

The spelling of 4114434433 in words is "four billion, one hundred fourteen million, four hundred thirty-four thousand, four hundred thirty-three".