411445544113 has 4 divisors (see below), whose sum is σ = 415290829680. Its totient is φ = 407600258548.

The previous prime is 411445544101. The next prime is 411445544137. The reversal of 411445544113 is 311445544114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 411445544113 - 2²¹ = 411443446961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (411445544143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1922642623 + ... + 1922642836.

It is an arithmetic number, because the mean of its divisors is an integer number (103822707420).

Almost surely, 2^411445544113 is an apocalyptic number.

It is an amenable number.

411445544113 is a deficient number, since it is larger than the sum of its proper divisors (3845285567).

411445544113 is a wasteful number, since it uses less digits than its factorization.

411445544113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3845285566.

The product of its digits is 76800, while the sum is 37.

Subtracting from 411445544113 its reverse (311445544114), we obtain a palindrome (99999999999).

The spelling of 411445544113 in words is "four hundred eleven billion, four hundred forty-five million, five hundred forty-four thousand, one hundred thirteen".