Base | Representation |
---|---|
bin | 10010101101101000010100… |
… | …10011000110110111111111 |
3 | 12101200220222222121001021002 |
4 | 21112310022103012313333 |
5 | 20343201210114202111 |
6 | 223304055501000515 |
7 | 11445002444355245 |
oct | 1126641223066777 |
9 | 171626888531232 |
10 | 41150254444031 |
11 | 121257a7937737 |
12 | 4747240b5313b |
13 | 19c65b5a4cb45 |
14 | a2397bdc8795 |
15 | 4b562c57363b |
hex | 256d0a4c6dff |
41150254444031 has 2 divisors, whose sum is σ = 41150254444032. Its totient is φ = 41150254444030.
The previous prime is 41150254444021. The next prime is 41150254444067. The reversal of 41150254444031 is 13044445205114.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41150254444031 - 222 = 41150250249727 is a prime.
It is a super-2 number, since 2×411502544440312 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41150254444021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20575127222015 + 20575127222016.
It is an arithmetic number, because the mean of its divisors is an integer number (20575127222016).
Almost surely, 241150254444031 is an apocalyptic number.
41150254444031 is a deficient number, since it is larger than the sum of its proper divisors (1).
41150254444031 is an equidigital number, since it uses as much as digits as its factorization.
41150254444031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 153600, while the sum is 38.
Adding to 41150254444031 its reverse (13044445205114), we get a palindrome (54194699649145).
The spelling of 41150254444031 in words is "forty-one trillion, one hundred fifty billion, two hundred fifty-four million, four hundred forty-four thousand, thirty-one".
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