41151412441 has 2 divisors, whose sum is σ = 41151412442. Its totient is φ = 41151412440.

The previous prime is 41151412417. The next prime is 41151412451. The reversal of 41151412441 is 14421415114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 41136358041 + 15054400 = 202821^2 + 3880^2 .

It is a cyclic number.

It is not a de Polignac number, because 41151412441 - 2¹³ = 41151404249 is a prime.

It is not a weakly prime, because it can be changed into another prime (41151412451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20575706220 + 20575706221.

It is an arithmetic number, because the mean of its divisors is an integer number (20575706221).

Almost surely, 2^41151412441 is an apocalyptic number.

It is an amenable number.

41151412441 is a deficient number, since it is larger than the sum of its proper divisors (1).

41151412441 is an equidigital number, since it uses as much as digits as its factorization.

41151412441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2560, while the sum is 28.

Adding to 41151412441 its reverse (14421415114), we get a palindrome (55572827555).

The spelling of 41151412441 in words is "forty-one billion, one hundred fifty-one million, four hundred twelve thousand, four hundred forty-one".