Base | Representation |
---|---|
bin | 10010101101101100001000… |
… | …01111101101000011111111 |
3 | 12101201010021120100222010022 |
4 | 21112312010033231003333 |
5 | 20343214402343402343 |
6 | 223305034504202355 |
7 | 11445104236435415 |
oct | 1126660417550377 |
9 | 171633246328108 |
10 | 41152300372223 |
11 | 121266577a3887 |
12 | 47477121693bb |
13 | 19c6850888141 |
14 | a23ad39db2b5 |
15 | 4b56ebea9568 |
hex | 256d843ed0ff |
41152300372223 has 4 divisors (see below), whose sum is σ = 41152431777408. Its totient is φ = 41152168967040.
The previous prime is 41152300372213. The next prime is 41152300372231. The reversal of 41152300372223 is 32227300325114.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 41152300372223 - 214 = 41152300355839 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (41152300372213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65231711 + ... + 65859552.
It is an arithmetic number, because the mean of its divisors is an integer number (10288107944352).
Almost surely, 241152300372223 is an apocalyptic number.
41152300372223 is a deficient number, since it is larger than the sum of its proper divisors (131405185).
41152300372223 is a wasteful number, since it uses less digits than its factorization.
41152300372223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 131405184.
The product of its (nonzero) digits is 60480, while the sum is 35.
Adding to 41152300372223 its reverse (32227300325114), we get a palindrome (73379600697337).
The spelling of 41152300372223 in words is "forty-one trillion, one hundred fifty-two billion, three hundred million, three hundred seventy-two thousand, two hundred twenty-three".
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