Base | Representation |
---|---|
bin | 10010101101101101100001… |
… | …11100100000000101010001 |
3 | 12101201012012211111220112011 |
4 | 21112312300330200011101 |
5 | 20343222421340004131 |
6 | 223305241134102521 |
7 | 11445131644016662 |
oct | 1126666074400521 |
9 | 171635184456464 |
10 | 41153050313041 |
11 | 12126a02053487 |
12 | 47478a134aa41 |
13 | 19c69400619c4 |
14 | a23b65455369 |
15 | 4b5742c440b1 |
hex | 256db0f20151 |
41153050313041 has 24 divisors (see below), whose sum is σ = 44051191129440. Its totient is φ = 38436218537472.
The previous prime is 41153050313017. The next prime is 41153050313059. The reversal of 41153050313041 is 14031305035114.
It is not a de Polignac number, because 41153050313041 - 223 = 41153041924433 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 41153050312994 and 41153050313012.
It is not an unprimeable number, because it can be changed into a prime (41153050311041) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 30380685 + ... + 31706341.
It is an arithmetic number, because the mean of its divisors is an integer number (1835466297060).
Almost surely, 241153050313041 is an apocalyptic number.
It is an amenable number.
41153050313041 is a deficient number, since it is larger than the sum of its proper divisors (2898140816399).
41153050313041 is a wasteful number, since it uses less digits than its factorization.
41153050313041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1326513 (or 1326496 counting only the distinct ones).
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 41153050313041 its reverse (14031305035114), we get a palindrome (55184355348155).
The spelling of 41153050313041 in words is "forty-one trillion, one hundred fifty-three billion, fifty million, three hundred thirteen thousand, forty-one".
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