Base | Representation |
---|---|
bin | 111011111010101010000… |
… | …011110101010000111101 |
3 | 112120121210220100021120011 |
4 | 323322222003311100331 |
5 | 1014430000020112033 |
6 | 12431304433023221 |
7 | 603321540563425 |
oct | 73725203652075 |
9 | 15517726307504 |
10 | 4117431800893 |
11 | 1348213a01794 |
12 | 565b9b6b4b11 |
13 | 23b36cbc5758 |
14 | 1033db561485 |
15 | 72185762ccd |
hex | 3beaa0f543d |
4117431800893 has 2 divisors, whose sum is σ = 4117431800894. Its totient is φ = 4117431800892.
The previous prime is 4117431800887. The next prime is 4117431800971. The reversal of 4117431800893 is 3980081347114.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2803973693049 + 1313458107844 = 1674507^2 + 1146062^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4117431800893 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4117431800813) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2058715900446 + 2058715900447.
It is an arithmetic number, because the mean of its divisors is an integer number (2058715900447).
Almost surely, 24117431800893 is an apocalyptic number.
It is an amenable number.
4117431800893 is a deficient number, since it is larger than the sum of its proper divisors (1).
4117431800893 is an equidigital number, since it uses as much as digits as its factorization.
4117431800893 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 580608, while the sum is 49.
The spelling of 4117431800893 in words is "four trillion, one hundred seventeen billion, four hundred thirty-one million, eight hundred thousand, eight hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •